Testing LaTex
03-17-2014, 10:43 PM (This post was last modified: 03-17-2014 10:43 PM by Tugdual.)
Post: #1
 Tugdual Senior Member Posts: 755 Joined: Dec 2013
Testing LaTex
Testing copy paste from Daum Equation Editor on Chrome.
Works damned well...
$$\zeta (2)=\sum _{ n=1 }^{ +\infty }{ \frac { 1 }{ { n }^{ 2 } } } =\frac { { \pi }^{ 2 } }{ 6 }$$
03-18-2014, 01:44 PM (This post was last modified: 03-18-2014 01:47 PM by Martin Paech.)
Post: #2 Martin Paech Junior Member Posts: 19 Joined: Dec 2013
RE: Testing LaTex
(03-17-2014 10:43 PM)Tugdual Wrote:  Works damned well...

Wow, I'm also impressed:

$$\tilde{\mathfrak{S}}_{N, \eta}(\nu_{k})\approx\frac{1}{\pi}\int_{\mathbb{R}}\mathrm{d}\omega\,S(\omega)\,​\frac{\eta}{(\nu_{k}-\omega)^{2}+\eta^{2}}\quad\text{for}\quad k=1, 2, \dots, M$$
03-18-2014, 03:51 PM
Post: #3 Martin Paech Junior Member Posts: 19 Joined: Dec 2013
RE: Testing LaTex
$$R=\big(\underbrace{r_{1}, r_{2}, \dots, r_{g_{1}}}_{\varrho^{}_{1}\;\text{,}\;\;r'_{1}=r^{}_{g_{1}}}, \underbrace{r_{g_{1}+1}, r_{g_{1}+2}, \dots, r_{g_{2}}}_{\varrho^{}_{2}\;\text{,}\;\;r'_{2}=r^{}_{g_{2}}}, \dots, \underbrace{r_{g_{u-1}+1}, r_{g_{u-1}+2}, \dots, r_{g_{u}}}_{\varrho^{}_{u}\;\text{,}\;\;r'_{u}=r^{}_{g_{u}}}\big)$$
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