HP Prime & HP 49G Problem with square roots
06-26-2014, 10:25 AM (This post was last modified: 06-26-2014 11:33 AM by Gerald H.)
Post: #1
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
HP Prime & HP 49G Problem with square roots
Some (irrelevant to this thread) calculations produced these two expressions:

√1201+√(70+2*√1201)

&

√(35+2*√6)+√(1236-2*√6+2*√(42035-2402*√6))

which should be equal. I have checked with the Longfloat Lib on the HP 49G, & the two are equal to many decimal positions, but are they in fact exactly equal?

Assistance appreciated.

(Title edited to include HP Prime, 13:33, 26/6)
06-26-2014, 10:45 AM
Post: #2
 Thomas Klemm Senior Member Posts: 1,447 Joined: Dec 2013
RE: HP 49G Problem with square roots
(06-26-2014 10:25 AM)Gerald H Wrote:  are they in fact exactly equal?

True
06-26-2014, 11:00 AM
Post: #3
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP 49G Problem with square roots
(06-26-2014 10:45 AM)Thomas Klemm Wrote:
(06-26-2014 10:25 AM)Gerald H Wrote:  are they in fact exactly equal?

True

Thank you.

I believe the result is correct & dislike relying on the authority of some cloud-computing; Why should I trust Wolframalpha if I have no means of checking the result?

My version of Maple is antiquated & can't deal with the question, nor can the HP 49G - & even if they did return an intelligible answer, I'd still want to know how.
06-26-2014, 11:01 AM
Post: #4
 CosmicTruth Member Posts: 164 Joined: May 2014
RE: HP 49G Problem with square roots
(06-26-2014 10:25 AM)Gerald H Wrote:  <clipped>these two expressions:
√1201+√(70+2*√1201)
&
√(35+2*√6)+√(1236-2*√6+2*√(42035-2402*√6))
<clipped>but are they in fact exactly equal?
Assistance appreciated.

50G says no

Thanks
~~~~8< Art >8~~~~

PS: Please post more 50G stuff :)
06-26-2014, 11:03 AM
Post: #5
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP 49G Problem with square roots
(06-26-2014 11:01 AM)CosmicTruth Wrote:
(06-26-2014 10:25 AM)Gerald H Wrote:  <clipped>these two expressions:
√1201+√(70+2*√1201)
&
√(35+2*√6)+√(1236-2*√6+2*√(42035-2402*√6))
<clipped>but are they in fact exactly equal?
Assistance appreciated.

50G says no

Thank you.

So now we have two authorities dsagreeing(see post #2)?
06-26-2014, 11:36 AM
Post: #6
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP Prime & HP 49G Problem with square roots
I have now tried the expressions on HP Prime CAS: for == a zero is returned & for - a value of -2.27373675443E-13.

The numerical value for - is certainly wrong.
06-26-2014, 04:08 PM
Post: #7
 Claudio L. Senior Member Posts: 1,687 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
My 2 cents:

I ran it in the newRPL demo at 2007 digits precision, and the difference between both expressions came out 1e-2005, so I'd say they are equal at least up to the first 2000 digits.

Claudio
06-26-2014, 04:25 PM
Post: #8
 Claudio L. Senior Member Posts: 1,687 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
To get an algebraic proof, I don't have the time but I think the key is:

Code:
 1201 = 35^2 - 2^2*6

Claudio
06-26-2014, 04:29 PM
Post: #9
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP Prime & HP 49G Problem with square roots
(06-26-2014 04:08 PM)Claudio L. Wrote:  My 2 cents:

I ran it in the newRPL demo at 2007 digits precision, and the difference between both expressions came out 1e-2005, so I'd say they are equal at least up to the first 2000 digits.

Claudio

Thank you for the confirmation - I hadn't tested to such precision.

The means by which the two expressions arose implies, I believe, equality & I'm not bright enough to demonstrate this equality.

More precision will (hopefully) corroborate equality, but a convincing reasoning would settle the matter.
06-26-2014, 05:58 PM (This post was last modified: 06-26-2014 07:06 PM by Manolo Sobrino.)
Post: #10
 Manolo Sobrino Member Posts: 179 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
OK, first let's notice that 1201 is prime, 42035=35*1201 and 1236=35+1201. Now rewrite the longer expression:

\sqrt{35+2\sqrt{6}}+\sqrt{1201+35-2\sqrt{6}+2\sqrt{\left(35-2\sqrt{6}\right)1201}}

That is the square of a sum: \sqrt{35+2\sqrt{6}}+\sqrt{\left(\sqrt{1201}+\sqrt{35-2\sqrt{6}}\right)^2}

You don't need to worry about the absolute value, it's simply:\sqrt{1201}+\sqrt{35+2\sqrt{6}}+\sqrt{35-2\sqrt{6}}

If a>b it's trivial to prove that:$$\sqrt{a+b}+\sqrt{a-b}=\sqrt{2a+2\sqrt{a^2-b^2}}$$
In this case: $$\sqrt{70+2\sqrt{1225-4\cdot 6}}=\sqrt{70+2\sqrt{1201}}$$
There you go.

(You guys should use paper and pencil more often )
06-26-2014, 06:49 PM
Post: #11
 Alberto Candel Member Posts: 169 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
This reminds me of Dedekind's Theorem that $$\sqrt{2} \sqrt{3} = \sqrt{6}$$. A very readable account is in the article "Dedekind's Theorem: ..." by Fowler in The American Mathematical Monthly Vol. 99, No. 8, Oct., 1992, p.725.
06-26-2014, 06:51 PM
Post: #12
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP Prime & HP 49G Problem with square roots
(06-26-2014 05:58 PM)Manolo Sobrino Wrote:  OK, first let's notice that 1201 is prime, 42035=35*1201 and 1236=35+1201. Now rewrite the longer expression:

\sqrt{35+2\sqrt{6}}+\sqrt{1201+35-2\sqrt{6}+2\sqrt{\left(35-2\sqrt{6}\right)1201}}

That is the square of a sum: \sqrt{35+2\sqrt{6}}+\sqrt{\left(\sqrt{1201}+\sqrt{35-2\sqrt{6}}\right)^2}

You don't need to worry about the absolute value, it's simply:\sqrt{1201}+\sqrt{35+2\sqrt{6}}+\sqrt{35-2\sqrt{6}}

If a>b it's trivial to prove that:$$\sqrt{a+b}+\sqrt{a-b}=\sqrt{2a+2\sqrt{a^2-b^2}}$$
In this case: $$\sqrt{70+2\sqrt{1225-4\cdot 6}}=\sqrt{70+\sqrt{1201}}$$
There you go.

(You guys should use paper and pencil more often )

The last calculation line is a typo?
06-26-2014, 07:15 PM
Post: #13
 Manolo Sobrino Member Posts: 179 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
(06-26-2014 06:51 PM)Gerald H Wrote:  The last calculation line is a typo?

Of course it was, fixed now. (LaTeX here seems to cause me dyslexia )
06-26-2014, 07:28 PM
Post: #14
 Gerald H Senior Member Posts: 1,438 Joined: May 2014
RE: HP Prime & HP 49G Problem with square roots
I take my hat off to you,Manolo Sobrino. Bravo!
06-26-2014, 07:37 PM
Post: #15
 Manolo Sobrino Member Posts: 179 Joined: Dec 2013
RE: HP Prime & HP 49G Problem with square roots
Thank you Gerald!
06-28-2014, 11:24 PM
Post: #16
 CosmicTruth Member Posts: 164 Joined: May 2014
RE: HP Prime & HP 49G Problem with square roots
HP50G calculator for sale or trade for good pencil and paper pad.

|
v

hehe jk

Thanks
~~~~8< Art >8~~~~

PS: Please post more 50G stuff :)
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