Algebraic manipulation
|
02-07-2019, 08:12 PM
Post: #1
|
|||
|
|||
Algebraic manipulation
Hi,
How can I manipulate a algebraic expression trying to extract a used defined term. Exemple: (4x-12) --> I know I can factor this term. Does exists any kind of control that I can specify a term? I would like to specif "(x-3)" --> 4.(x-3) Another Exemple: (3-(4/5x)-(-5) --> I would like to specify a term "(x-10)" and see it´s possible. Does the calculator can do that? Or any alternative? Thanks |
|||
02-08-2019, 01:04 AM
Post: #2
|
|||
|
|||
RE: Algebraic manipulation
I don't know of a way to use a specific factor.
Alternatives:
|
|||
02-08-2019, 09:52 AM
Post: #3
|
|||
|
|||
RE: Algebraic manipulation
I think "factor()" and "simplify" will do the trick
![]() Oh … and make sure you're in the CAS "ambient" ! Best, Aries ![]() |
|||
02-08-2019, 05:37 PM
Post: #4
|
|||
|
|||
RE: Algebraic manipulation
Usually , I ´ve been using the factor and simplify command as mentioned. But I would like to specify a factor if possible...
![]() Thanks Best, Mario |
|||
02-09-2019, 10:48 PM
Post: #5
|
|||
|
|||
RE: Algebraic manipulation
Bruce,
I like your strategy the best - use the simplify(p(x)/q(x)). The CAS program specfactor uses this strategy to factor q(x) from p(x): Code:
Successful factoring returns the result as strings (to preserve the format without automatic simplification): specfactor(4x-12,x-3) returns "(4)*(x-3)" [ 4(x-3) ] specfactor(8-4/5*x,x-10) returns "(-0.8)*(x-10)" specfactor(x^3 -x^2+2*x-2,x^2+2) returns "(x-1)*(x^2+2)" Eddie |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 1 Guest(s)