[VA] SRC #010 - Pi Day 2022 Special
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03-22-2022, 12:14 AM
Post: #16
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RE: [VA] SRC #010 - Pi Day 2022 Special
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Hi, all, (03-18-2022 04:22 PM)Albert Chan Wrote: Lets recover true PN, and compare errors of products vs exp(sum of logs) [...] Note that ln(C) is odd function. Rewrite ln(C) as polynomial of 1/N, we have: I must point out that this formal series of correction factors is asymptotic and divergent, i.e., its coefficients might be small and even decreasing for a while but eventually they grow bigger and bigger, both numerators and denominators, and thus can't be used to obtain arbitrary precision, as I explained in another case in post #27 of my Short & Sweet Math Challenge #24. Quoting myself from that post: Quote: The same happens in the present case: you can use a certain number of coefficients to improve accuracy up to the "sweet point" of maximum accuracy, but after that the accuracy quickly degrades and thus using more coefficients is useless and to be avoided. Quote:PI * PI + → 3.141608361513791562872866895754895 // true PN Regrettably, presently I have no software available to compute the product for n = 2 to n = 100,000 with high accuracy (say, to 100 digits) so I can't check for sure, but I find it somewhat hard to believe that my computation using the 34 digits afforded by Free42 Decimal would lose 11 digits in the process, I'd rather expect 6-7 digits lost at most. Likewise, Jean-François Garnier computation of said product using logarithms performs about 100,000 multiplications, divisions (1/x) and logarithms (LN1+X) but only loses 3 digits ? Really ? To settle down the question, if someone with access to Mathematica or some other arbitrary-precision software can compute the product for N=100,000 using 100 digits, say, or as many as necessary to ensure full 34 correct digits or more, and post here the resulting value I'd appreciate it. Thanks in advance. V. All My Articles & other Materials here: Valentin Albillo's HP Collection |
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