Try to plot x^(2/3).. what happen for x<0 ?
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08-22-2019, 06:45 AM
Post: #2
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RE: Try to plot x^(2/3).. what happen for x<0 ?
I assume the Prime does simpy follow the basic rules of Mathematics:
In the first expression, we start with squaring x, which yields for all reals a positive result - thus the cubic root is defined everywhere. In the second expression, the cubic root is calculated first - but for reals is only defined for x >= 0. Thus the plot is left for x < 0. |
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Messages In This Thread |
Try to plot x^(2/3).. what happen for x<0 ? - josephec - 08-22-2019, 03:45 AM
RE: Try to plot x^(2/3).. what happen for x<0 ? - rkf - 08-22-2019 06:45 AM
RE: Try to plot x^(2/3).. what happen for x<0 ? - ijabbott - 08-22-2019, 08:08 AM
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