08-22-2019, 03:45 AM
08-22-2019, 06:45 AM
I assume the Prime does simpy follow the basic rules of Mathematics:
In the first expression, we start with squaring x, which yields for all reals a positive result - thus the cubic root is defined everywhere.
In the second expression, the cubic root is calculated first - but for reals is only defined for x >= 0. Thus the plot is left for x < 0.
In the first expression, we start with squaring x, which yields for all reals a positive result - thus the cubic root is defined everywhere.
In the second expression, the cubic root is calculated first - but for reals is only defined for x >= 0. Thus the plot is left for x < 0.
08-22-2019, 08:08 AM
You can redefine the second one as \( \big( \sqrt[3]{x}\big)^2 \) to square the real cube root of \( x\).
Note that \(x^\frac{1}{3}\) and \(\sqrt[3]{x}\) are treated differently, and that \(x^\frac{1}{3}\) usually produces a complex number when \( x < 0 \), and its square is also complex, so it cannot be plotted by the Function app.
Note that \(x^\frac{1}{3}\) and \(\sqrt[3]{x}\) are treated differently, and that \(x^\frac{1}{3}\) usually produces a complex number when \( x < 0 \), and its square is also complex, so it cannot be plotted by the Function app.