Simple parallel circuit problem

[Gerson W. Barbosa]

(08-28-2015 03:23 AM)Garth Wilson Wrote:  I don't know what you mean by "E24" resistors, but we have:
3 / (15.06K // 183 // 1 // 24) = Pi A

Code:

3
ENTER
15060
1/X
183
1/X
+
24
1/X
+
1
+
1/X    \ Not quite the most efficient,
/      \ but just to show what's done.

Likewise, 2 ENTER 20000 1/x 110 1/x + 10 1/x + 4 1/x + 1 + 1/x / = e A.

Parallel resistors values courtesy of Wolfram Alpha:

http://www.wolframalpha.com/input/?i=Egy...1000000000

http://www.wolframalpha.com/input/?i=Egy...1000000000

I should have written "E24 series resistors", but since this involves resistors in parallel I thought this might be a bit confusing. Those E24 resistors are easily available, but I guess no one would want to build a physical circuit. Anyway, 5% tolerance would be too much for this application :-)

http://www.logwell.com/tech/components/r...alues.html