About HP Prime factorization

11032020, 03:46 AM
Post: #5




RE: About HP Prime factorization
(11022020 07:32 PM)Albert Chan Wrote: Hi, dah145 Yes thanks, this definitely is what I was looking for. Now I wonder if it is possible to obtain the expressions in form of a product, say: (a^2  2*a*b + b^2 + s^2)*(a^2  2*a*b + b^2 + s^2) = (s^2+(ab)^2)*(s^2+(ab)^2), as using your custom function outputs a not so friendly expression: s^2*(2*(a^2 + b^2) + s^2)+(a+b)^2*(ab)^2. 

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Messages In This Thread 
About HP Prime factorization  dah145  11022020, 06:28 AM
RE: About HP Prime factorization  parisse  11022020, 07:58 AM
RE: About HP Prime factorization  dah145  11022020, 05:40 PM
RE: About HP Prime factorization  Albert Chan  11022020, 07:32 PM
RE: About HP Prime factorization  dah145  11032020 03:46 AM
RE: About HP Prime factorization  dah145  11192020, 04:12 PM

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