testing ibpdv and ibpu

05122015, 01:57 PM
Post: #1




testing ibpdv and ibpu
hi all,
I'm testing the "integration by parts" in the Prime. Inputting ibpu(x*sin(x),x) I get [x*cos(x) cos(x)], ok with ibpdv(x*sin(x),sin(x) I get [x*sin(x)^2/cos(x) (x*sin(x)^3cos(x)*sin(x)^2x*cos(x)^2)/cos(x)^2] I'm a bit confused: shouldn't I get the same result as above? Am I using wrong syntax? :) Then another question: there is also a "integration by substitution" method in the Prime? thank you Salvo ∫aL√0mic (IT9CLU) :: HP Prime 50g 41CX 71b 42s 39s 35s 12C 15C  DM42, DM41X  WP34s Prime Soft. Lib 

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