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How to solve ncdf(X, 0.76, 83, 1E99) = 0.15 (RESOLVED)
04-27-2015, 08:18 PM
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RE: How to solve ncdf(X, 0.76, 83, 1E99) = 0.15
(04-27-2015 07:23 PM)Dieter Wrote:  Hmmm... does the Prime really have no quantile functions that give a direct result?
Here's how you do it on a 34s:

83 STO J   0,76 STO K
0,15 Norml–1 => 82,21231062398472

Dieter

The Prime can solve directly for x with: NORMALD_ICDF(83,0.76,0.15)

In this example, the WP34S used ~16-19 keystrokes depending on PROB menu navigation. The Prime takes ~14 or more depending on having to go to the on-board HELP to guide the syntax to use.
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RE: How to solve ncdf(X, 0.76, 83, 1E99) = 0.15 - CR Haeger - 04-27-2015 08:18 PM



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