How to solve ncdf(X, 0.76, 83, 1E99) = 0.15 (RESOLVED)

[StephanP]

While evaluating the HP Prime, I am trying to sort out how to do the things I usually do on my TI-84.

I can't seem to find how to solve the following equation:

ncdf(X, 0.76, 83, 1E99) = 0.15

normald_CDF( u0=X, sd=-.76, left bound=83, right bound = 1E99)
area (probability) = 0.15

On TI-84 I would do the following:
Y1 = normalcdf(83, 1E99, X, 0.76)
Y2 = 0.15
Adjust window settings, Graph and Calculate intersect

   

How would I do this on the HP Prime?