(HP15C)(HP67)(HP41C) Bernoulli Polynomials

08302023, 09:58 AM
Post: #9




RE: (HP15C)(HP67)(HP41C) Bernoulli Polynomials
(08292023 09:16 PM)John Keith Wrote: The problem here is that all useful methods of calculating Bernoulli numbers involve fairly large numbers, and the classic hp's can only represent numbers < 10^10 exactly. Albert's method using Stirling numbers may be better than nested summation but will still see cancellation errors for n > 16. Thanks John for the hint and the link. I am off today for a few weeks vacation in Europe (which kicks off with attending the wedding of a nephew in Greece!), so I may be slow in digesting the Euler Sizgzag numbers. They do look interesting! Namir 

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