Pi Approximation Day
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07-25-2022, 06:38 AM
Post: #32
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RE: Pi Approximation Day
(07-25-2022 12:03 AM)Albert Chan Wrote: 3 SQRT 2 + // cot(pi/12) ≈ 3.732 Now we're close enough to 0 that using only the first two terms of the Taylor series of the \(\arctan(x)\) function gives a good approximation for \(\pi\): \( \begin{align} \arctan(x)\approx x-\frac{x^{3}}{3} \end{align} \) So we can continue with: ENTER ENTER X↑2 × 3 ÷ - 96 × 3.14159193225 Instead of: ENTER X^2 1 + SQRT + we could also use: 1 X<>Y →POL LASTX + |
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