Catenoid soap bubbles
11-07-2021, 08:08 PM
Post: #6
 ijabbott Senior Member Posts: 1,229 Joined: Jul 2015
RE: Catenoid soap bubbles
(11-07-2021 04:27 PM)Albert Chan Wrote:  I don't understand the complexity.

Let R = D/2 = 1.068/2 = 0.534 m
Let H = L/2 = 0.5/2 = 0.25 m

First, with symmetry, b = 0.25 m (not need to solve at all)
Shift axis so that x=0 has radius of r (= Matt's a), x=H have radius of R

Yes, it looked a bit suspicious when he got a b value exactly half of the length (+/- epsilon). Obviously symmetrical.

For different top and bottom radii, you really would have to solve for both a and b. It looks like Matt's Python code could be easily modified to handle different diameters at each end.

— Ian Abbott
 « Next Oldest | Next Newest »

 Messages In This Thread Catenoid soap bubbles - ijabbott - 11-06-2021, 07:51 PM RE: Catenoid soap bubbles - C.Ret - 11-07-2021, 12:11 PM RE: Catenoid soap bubbles - Albert Chan - 11-07-2021, 04:27 PM RE: Catenoid soap bubbles - ijabbott - 11-07-2021 08:08 PM RE: Catenoid soap bubbles - Albert Chan - 11-08-2021, 01:56 PM RE: Catenoid soap bubbles - Wes Loewer - 11-07-2021, 05:44 PM RE: Catenoid soap bubbles - ijabbott - 11-07-2021, 07:56 PM RE: Catenoid soap bubbles - ijabbott - 11-08-2021, 04:28 PM RE: Catenoid soap bubbles - Albert Chan - 11-08-2021, 06:03 PM RE: Catenoid soap bubbles - Joe Horn - 11-09-2021, 02:57 AM RE: Catenoid soap bubbles - ijabbott - 11-09-2021, 08:29 AM

User(s) browsing this thread: 1 Guest(s)