Cube root [HP-35]

[Gerson W. Barbosa]

(03-16-2020 02:42 PM)Albert Chan Wrote:  We can use Pade approximation to speedup convergence.

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For cube roots, we have: \(\large\sqrt[3]k ≈ x \left({2k\;+\; x^3 \over k\;+\;2x^3 } \right) \)

Very nice! For k = 27 and x₀ = √√27 I get 3.00000000001 after 3 iterations. Thanks!