[VA] Short & Sweet Math Challenge #24: "2019 Spring Special 5-tier"

[Gilles]

(03-28-2019 12:38 AM)Valentin Albillo Wrote:  Tier 1 - The Challenge:
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Also, being a 10-digit number and having all its digits distinct means that its digits are 0, 1, 2, 3, ... , 9 in some order and thus their sum is 1 + 2 + 3 + ... + 9 = 45, which is divisible by 9 so each Homage number has to be divisible by 9 too. As 9 is coprime to 41 and 271, each Homage number N must be divisible by their product, i.e., by 41 * 271 * 9 = 99,999.
 

Good catch the divisibility by 9. I totaly missed this.