Solving sqrt(i)=z, one or two solutions?

[Albert Chan]

(10-25-2018 05:14 PM)ijabbott Wrote:  So you're objecting to it factoring out the radical part as a real number? I think \(\frac{1+i}{\sqrt{2}}\) is easier to visualize than \(\sqrt{i}\).

I think sasa wanted both of the roots.
So, the idea is to return sqrt(i), unevaluated.

Multiple solutions also work, so sqrt(z) is not mapped 1-to-1, but 1-to-2

http://mathforum.org/library/drmath/view/52243.html