"What is the area? You should be able to solve this"

08082018, 01:51 PM
(This post was last modified: 08082018 01:53 PM by Albert Chan.)
Post: #19




RE: "What is the area? You should be able to solve this"
There is another way to solve top right area without inner square:
Let P = (x,y), inside the square with side = 2 With P, square splitted into 4 triangles, all with base=2, thus triangle area = height Triangle Area: Left, Bottom, Right, Top = x, y, 2x, 2y SB = 1/2 (Left + Bottom) = (x + y)/2 SX = 1/2 (Right + Top) = 2  (x + y)/2 SB + SX = 2 SA + SC = 2*2  (SB + SX) = 4  2 = 2 SX = 2  SB = SA+ SC  SB = (16 + 32  20) cm^2 = 28 cm^2 

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