"What is the area? You should be able to solve this"
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08-08-2018, 01:51 PM
(This post was last modified: 08-08-2018 01:53 PM by Albert Chan.)
Post: #19
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RE: "What is the area? You should be able to solve this"
There is another way to solve top right area without inner square:
Let P = (x,y), inside the square with side = 2 With P, square splitted into 4 triangles, all with base=2, thus triangle area = height Triangle Area: Left, Bottom, Right, Top = x, y, 2-x, 2-y SB = 1/2 (Left + Bottom) = (x + y)/2 SX = 1/2 (Right + Top) = 2 - (x + y)/2 SB + SX = 2 SA + SC = 2*2 - (SB + SX) = 4 - 2 = 2 SX = 2 - SB = SA+ SC - SB = (16 + 32 - 20) cm^2 = 28 cm^2 |
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