How to evaluate A Taylor series at a specific value

08242018, 07:42 AM
(This post was last modified: 08242018 09:03 AM by Albert Chan.)
Post: #29




RE: How to evaluate A Taylor series at a specific value
(08222018 07:52 PM)parisse Wrote: It's hard to evaluate . You don't want to get sin(1) for sin(x)x=2 if x:=1; has been run, (08242018 06:21 AM)parisse Wrote: This is wrong: x:=1 followed by sin(x)x=2 returns sin(2), and that's not easy to evaluate I am confused. What situation will sin(x)x=2 return sin(1) ? Edit: Sorry for the noise. Above expression always return sin(2) 

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