A somewhat different Newton solver (HP35s)

[Dieter]

(09-26-2018 09:05 AM)Ángel Martin Wrote:  

Code:

10 RCL 01       ; h         ∆x/h
11 *            ; ∆x
12 RND         ;~∆x
13 ST- 00       ; x' = x - ∆x
14 X#0?         ; ∆x ~ 0 ?
15 GTO 00       ; loop

I don't think it's a good idea to round the calculated ∆x to display precision and then adjust x by this lower-precision value. So you should first adjust x (ST– 00) and then RND the delta and do the X≠0 test. Simply swap line 12 and 13.

Dieter