# Line slope calculator 7x+8y=64

**Straight line given by points A[0; 8] and B[8; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.875x+8

**Canonical form of the line equation:**7x+8y-64 = 0

**Parametric form of the line equation:**

x = 8t

y = -7t+8 ; t ∈ R

**Slope:**m = -0.875

**Slope angle of line: φ =**-41°11'9″ = -0.7188 rad

**X intercept:**x

_{0}= 9.1429

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 6.0206

**The length of the segment AB: |AB| =**10.6301

**Vector: AB =**(8; -7)

**Normal vector: n =**(7; 8)

**Midpoint of the segment AB: M =**[4; 4.5]

**Perpendicular Bisector equation:**8x-7y-0.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (8; 1) ; |OB| = 8.0623**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 82°52'30″ = 1.4464 rad**