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Programming Challenge: a classic trigonometry problem
01-07-2014, 06:03 AM (This post was last modified: 01-07-2014 06:13 AM by Thomas Klemm.)
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RE: Programming Challenge: a classic trigonometry problem
(01-06-2014 12:23 AM)Gerson W. Barbosa Wrote:  Same as Bunuel's method, I think.

Wikipedia provides yet another solution: Crossed ladders problem
\[ x^3(x-c)=1 \]
Which leads to:
\[ x=\frac{1}{x^3}+c \]
This equation can be solved iterating the following program:

001 \(x^3\)
002 1/x
003 RCL+ C


For C use: \(\frac{60}{\sqrt{700}}\).
Start with x = 2.
After 12 runs the value doesn't change anymore: 2.34530476375
Can it be any shorter?

Cheers
Thomas
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RE: Programming Challenge: a classic trigonometry problem - Thomas Klemm - 01-07-2014 06:03 AM



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