challenge for programmable calculators
|
12-26-2013, 06:19 AM
Post: #49
|
|||
|
|||
RE: challenge for programmable calculators
Or just have a look at the roots: {0.04974, 0.857089, 1.50476, 15.5884}
Since \(f(1)=1\) it's obvious that \(f(n)<0\) for n in {2,...,15}. To show this for n = 15 with your method isn't possible. In this case we're lucky that we don't have to do that. |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 2 Guest(s)