An iteration produces all the prime numbers

[peacecalc]

Hello all,

is there a relation between the precision of that constant and which greatest prime you can produce with it. That would be fancy: Let's say you know the constant with n decimal precision and the highest prime you can produce is say p(n). And with that prime you can improve this constant to a precision n+1 (or more) and with that you can produce the greatest prime let it call P(n+1) which is the successor of p(n), or the next two (or more) successors of p(n)...

Why I have to think about Münchhausen's lift oneself up by his own bootstraps?