HP50g simplifing a root
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10-04-2020, 06:05 PM
(This post was last modified: 10-04-2020 06:06 PM by peacecalc.)
Post: #9
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RE: HP50g simplifing a root
Hello Albert,
I tried two way, the first was to probe every small a from 1 until third root of A. From your example a has to tested from 1 to 670, what a luck, that a = 99. My second approach is to calculate every divisor of A (with DIVI) as a possible candidate for small a. Then I'm calculate the difference A - third power of a. Negative results can be sorted out. The rest is divided by 3*k*a and be square rooted. If the result is a integer and not a algebraic expression would be a solution for smal b. and we get: \[ \left( A\pm B\cdot\sqrt{k} \right)^{1/3} = a \pm b\cdot\sqrt{k} \]. For me the second approach makes mor sense, because the numbers of possibilities can be reduce very fast. Code:
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