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Cut the Cards
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08-28-2020, 11:39 PM
Post: #17
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RE: Cut the Cards
For the inverse digamma function I’ve been using a continued fraction with increasing number of terms. I am sure about only the first half of them, though. It’s difficult to be sure about the other half when one is limited to only 12 digits.
\(\rm{e}^{{x}}+\frac{1}{2+\frac{1}{6\rm{e}^{{x}}-\frac{1}{2+\frac{1}{\rm{e}^{{x}-1}-\frac{1}{2+\frac{1}{\rm{e}^{{x}}+\frac{1}{2}}}}}}}\) |
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Cut the Cards - David Hayden - 07-30-2020, 08:00 PM
RE: Cut the Cards - Albert Chan - 07-30-2020, 08:58 PM
RE: Cut the Cards - Albert Chan - 08-21-2020, 11:00 PM
RE: Cut the Cards - Jim Horn - 07-30-2020, 09:49 PM
RE: Cut the Cards - John Keith - 07-31-2020, 12:24 AM
RE: Cut the Cards - Gerson W. Barbosa - 08-24-2020, 01:57 PM
RE: Cut the Cards - Albert Chan - 08-25-2020, 06:14 PM
RE: Cut the Cards - Albert Chan - 07-30-2020, 10:21 PM
RE: Cut the Cards - pinkman - 08-24-2020, 09:49 PM
RE: Cut the Cards - Gerson W. Barbosa - 08-25-2020, 11:41 PM
RE: Cut the Cards - Albert Chan - 08-26-2020, 03:06 AM
RE: Cut the Cards - Gerson W. Barbosa - 08-26-2020, 08:23 AM
RE: Cut the Cards - Albert Chan - 08-26-2020, 02:13 PM
RE: Cut the Cards - Gerson W. Barbosa - 08-26-2020, 06:13 PM
RE: Cut the Cards - Gerson W. Barbosa - 08-27-2020, 10:07 PM
RE: Cut the Cards - Albert Chan - 08-28-2020, 09:26 PM
RE: Cut the Cards - Albert Chan - 08-29-2020, 04:02 PM
RE: Cut the Cards - Gerson W. Barbosa - 08-28-2020 11:39 PM
RE: Cut the Cards - Albert Chan - 06-23-2021, 12:08 AM
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