HP42s first major program (Double Integral) Best way to approach?
|
06-02-2020, 08:02 PM
Post: #46
|
|||
|
|||
RE: HP42s first major program (Double Integral) Best way to approach?
Hi, DM48
HV(c,c) involve calculating K(1) = ∞, thus Divide by 0 error. The fix required another rule: HV(c,c) = 2/3*c^3 For a=48, b=58, c=48: HV(58,48) ≈ 94954.7588409 HV(48,48) = 2/3*48^3 = 73728 Difference ≈ 21226.7588409 |
|||
« Next Oldest | Next Newest »
|
User(s) browsing this thread: 1 Guest(s)