Double integral fail, works on TI

[CyberAngel]

(04-02-2020 12:33 PM)parisse Wrote:  The default accuracy of the Prime prevents computation, because the inner integrand is singular at y=x and y=-x. If you set epsilon:=1e-6, you will get an answer
epsilon:=1e-6;
f:=exp(-x*y)/sqrt(x^2-y^2);
int(int(f,y,-x,x),x=0.0..1.0)
-> 3.30422650539
Of course precision is less than 1e-6!

I quickly tested this (1E-6, 1E-7) and 1E-8 gives interesting warnings on my Android Emu.
– –
VPN