(25) Binomial Probability Distribution

[PedroLeiva]

Another example
EXAMPLE2:
20 trials, P= 20%, what is the probability that 0-6 trials succeed? and 1 succeed?
n= 20
P= 0,2
r MIN= 0
r MAX= 6
P(0 to 6 successes) = .0115 + .0576 + .1369 + .2054 + .2182 + .1746 + .1091 = .9133
==> so cumulative probability= 0,9133 or 91.33%
P(0 success) = .0115
==> P(1 success) = .0576 or 5.76%
also…..
P(6 successes) = .1091
(TYVM to Albert Chan for the corrections !!)

I try with RPN GO-25 and it only takes a few seconds

Pedro