Newton's method
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11-06-2019, 04:42 PM
(This post was last modified: 11-06-2019 04:44 PM by Wes Loewer.)
Post: #7
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RE: Newton's method
(11-06-2019 06:48 AM)hazimrassam Wrote: The formula is simply Xn-[f(Xn)/f'(Xn)] Are you wanting just to solve the equation using Newton's Method? If so, then the online help that the others mentioned will give you that info. (Look for the newton() and fsolve() functions.) However, it sounds like you might be asking how to easily step through Newton's Method so that you can see the intermediate results. If so, what I find helpful with my students is to use the following: To find the zeros of x^3+x+1, enter an initial guess and then use X-(X^3+X+1)/(3*X^2+1)|(X=Ans) and press Enter repeatedly till the result starts to repeat. You could also use Ans-(Ans^3+Ans+1)/(3*Ans^2+1) but that's not as easy to type, nor is it as aesthetically pleasing. |
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Messages In This Thread |
Newton's method - hazimrassam - 11-05-2019, 09:09 PM
RE: Newton's method - Tim Wessman - 11-06-2019, 01:12 AM
RE: Newton's method - hazimrassam - 11-06-2019, 06:48 AM
RE: Newton's method - Wes Loewer - 11-06-2019 04:42 PM
RE: Newton's method - CyberAngel - 11-06-2019, 06:29 PM
RE: Newton's method - Tim Wessman - 11-06-2019, 01:39 PM
RE: Newton's method - DrD - 11-06-2019, 04:14 PM
RE: Newton's method - ThomasA - 11-06-2019, 04:38 PM
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