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HP 50g Double factorial
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05-01-2019, 01:40 PM
(This post was last modified: 05-01-2019 02:00 PM by Gilles.)
Post: #2
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RE: HP 50g Double factorial
Hi Joerg , another way is :
Code: « -> n 'IFTE(n MOD 2,(n+1)!/(2^((n+1)/2)*((n+1)/2)!),2^(n/2)*(n/2)!)'»returns 1 for zero, and an error for n<0 And works in symbolic mode with a symbolic variable |
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