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Solving x^y=y^x
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10-24-2018, 07:21 PM
Post: #2
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RE: Solving x^y=y^x
solve(subst(x^y=y^x, y=t*x), x) ==> [ t^(1/(t-1)) ]
So, [x, y] = [ t^(1/(t-1)), t^(t/(t-1)) ] But, I may have discovered a XCas bug ... solve([x^y=y^x, y=t*x], x) ==> *crash* |
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| Messages In This Thread |
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Solving x^y=y^x - sasa - 10-24-2018, 06:06 PM
RE: Solving x^y=y^x - Albert Chan - 10-24-2018 07:21 PM
RE: Solving x^y=y^x - Dieter - 10-24-2018, 07:37 PM
RE: Solving x^y=y^x - John Keith - 10-24-2018, 08:23 PM
RE: Solving x^y=y^x - CyberAngel - 10-28-2018, 08:22 PM
RE: Solving x^y=y^x - sasa - 10-24-2018, 08:45 PM
RE: Solving x^y=y^x - Albert Chan - 10-24-2018, 09:58 PM
RE: Solving x^y=y^x - ijabbott - 10-24-2018, 10:35 PM
RE: Solving x^y=y^x - Erwin - 10-26-2018, 04:54 PM
RE: Solving x^y=y^x - Albert Chan - 10-28-2018, 08:21 PM
RE: Solving x^y=y^x - Erwin - 10-28-2018, 08:51 PM
RE: Solving x^y=y^x - Tim Wessman - 10-29-2018, 03:14 AM
RE: Solving x^y=y^x - sasa - 10-24-2018, 07:45 PM
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