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OEIS A229580 mini challenge (RPL)
05-02-2018, 02:59 PM
Post: #25
Valentin Albillo Offline
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RE: OEIS A229580 mini challenge (RPL)
(05-02-2018 12:14 PM)Gerson W. Barbosa Wrote:  I arrived at that OEIS sequence when testing a continued fraction with consecutive denominators 3, 20 and 112. Since a continued fraction is evaluated backwards, a recursive formula wouldn’t help.

Would you please elaborate on this ? What's the particular, complete continued fraction ? What makes you think a recursive formula wouldn't help ?

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V.
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RE: OEIS A229580 mini challenge (RPL) - Valentin Albillo - 05-02-2018 02:59 PM



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