Lambert function and Wolfram or "±infinity+i×K=±infinity" ?

[Nigel (UK)]

(01-16-2024 03:40 PM)Gil Wrote:  Wolfram Alpha

LambertW (-infinity) = (infinity)

But (infinity) * EXP (infinity) can't be equal to -infinity

Can Wolfram Alpha be wrong?

Not in this case (although in general I’m sure it can be!). \(\exp(+\infty+{\rm i}\pi)\) is indeed \(-\infty\) because \(\exp({\rm i}\pi)=-1\). So far as I can see you’ve already said something like this a couple of posts ago, so maybe I’m not understanding what you are asking?

Nigel (UK)