How to easily crash an HP Prime
03-06-2018, 09:09 AM
Post: #1
 Ummon Junior Member Posts: 1 Joined: Mar 2018
How to easily crash an HP Prime

1. Put the calculator in degree mode
2. In numeric mode evaluate an integral from 0 to 10 of sin(X^2)dX
3. The calculator reboot nearly instantaneous

It also crashes with the virtual calculator on Windows.
03-07-2018, 02:04 PM
Post: #2
 Marcel Member Posts: 152 Joined: Mar 2014
RE: How to easily crash an HP Prime
Hi!

Same for me... my calculator reboot.

Marcel
03-07-2018, 03:11 PM
Post: #3
 Arno K Senior Member Posts: 430 Joined: Mar 2015
RE: How to easily crash an HP Prime
Funny enough that you tried to integrate a trigonometric function in degrees.
Arno
03-07-2018, 05:34 PM
Post: #4
 Marcel Member Posts: 152 Joined: Mar 2014
RE: How to easily crash an HP Prime
Hi,
Here, the angular mode is not the problem..
The prime don't have to reboot on this simple calculation.
Marcel
03-07-2018, 07:23 PM
Post: #5
 John Colvin Member Posts: 165 Joined: Dec 2013
RE: How to easily crash an HP Prime
Mine crashes also. Interestingly, the same integral dosen't crash my 49G+ in degree
mode, but it does give an incorrect answer - 4.66682...
But the fact remains that the Prime should not crash simply because the degree
03-08-2018, 04:48 AM (This post was last modified: 03-08-2018 04:57 AM by Carsen.)
Post: #6
 Carsen Member Posts: 141 Joined: Jan 2017
RE: How to easily crash an HP Prime
John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order?

"The Common Man's Collapse" by Veil Of Maya. BEST ALBUM EVER!
03-08-2018, 05:04 AM
Post: #7
 Joe Horn Senior Member Posts: 1,347 Joined: Dec 2013
RE: How to easily crash an HP Prime
(03-08-2018 04:48 AM)Carsen Wrote:  My HP 50g got the right answer of 4.66829167156.

Your answer is what the 50g gets in FIX 4 mode, leaving a pretty big value stored in IERR. STD mode takes a few seconds longer but returns 4.66829104623 with a much smaller IERR.

X<> c
-Joe-
03-08-2018, 06:37 AM
Post: #8
 parisse Senior Member Posts: 911 Joined: Dec 2013
RE: How to easily crash an HP Prime
This bug is already fixed in source code. Until it is available in a new firmware, you can run int(sin(x^2),x,0,10.0)
03-08-2018, 06:45 AM
Post: #9
 Carsen Member Posts: 141 Joined: Jan 2017
RE: How to easily crash an HP Prime
(03-08-2018 05:04 AM)Joe Horn Wrote:
(03-08-2018 04:48 AM)Carsen Wrote:  My HP 50g got the right answer of 4.66829167156.

Your answer is what the 50g gets in FIX 4 mode, leaving a pretty big value stored in IERR. STD mode takes a few seconds longer but returns 4.66829104623 with a much smaller IERR.

Huh. That's neat. I did not know about Integration Error (IERR) variable. I also didn't know (or forgot) that the number format changes the precision of the answer. Like the 15C. Learn something new everyday. Thanks Joe Horn.

"The Common Man's Collapse" by Veil Of Maya. BEST ALBUM EVER!
03-08-2018, 02:41 PM
Post: #10
 DA74254 Member Posts: 65 Joined: Sep 2017
RE: How to easily crash an HP Prime
I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1

Esben
28s, 35s, 49G+, 50G, Prime, SwissMicros DM42
Elektronika MK-52 & MK-61
03-08-2018, 03:04 PM (This post was last modified: 03-08-2018 03:06 PM by jebem.)
Post: #11
 jebem Senior Member Posts: 1,262 Joined: Feb 2014
RE: How to easily crash an HP Prime
(03-08-2018 02:41 PM)DA74254 Wrote:  I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1

"SM42" or "DM42"?

Anyway, it is always better to experience a machine reset than an infinite loop, so in this regard the HP Prime wins hands down

Jose Mesquita

03-08-2018, 03:20 PM
Post: #12
 DA74254 Member Posts: 65 Joined: Sep 2017
RE: How to easily crash an HP Prime
(03-08-2018 03:04 PM)jebem Wrote:
(03-08-2018 02:41 PM)DA74254 Wrote:  I tried in on my SM42. It went into an indefinite loop. Even with accuracy of 0.1

"SM42" or "DM42"?

Anyway, it is always better to experience a machine reset than an infinite loop, so in this regard the HP Prime wins hands down

SM DM42
Anyway, I was a bit quick as I set up sin (x^3) which went on and on. With the correct integration it spent abt 4 sec. to get 0.5836... in RAD and almost instantly 4.6682... in DEG mode. (And 4.3825... in GRAD mode)

Esben
28s, 35s, 49G+, 50G, Prime, SwissMicros DM42
Elektronika MK-52 & MK-61
03-08-2018, 08:25 PM
Post: #13
 John Colvin Member Posts: 165 Joined: Dec 2013
RE: How to easily crash an HP Prime
(03-08-2018 04:48 AM)Carsen Wrote:  John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order?

Am I missing something here? How is 4.6668.... the correct answer? If I convert
10 deg. to pi/18 red. in the upper boundary, I get a result of 0.001772.... on my
50G as well. A graph of sin(x^2) clearly indicates that in this interval, the area
under the curve is quite small.
03-08-2018, 08:47 PM (This post was last modified: 03-08-2018 08:54 PM by Joe Horn.)
Post: #14
 Joe Horn Senior Member Posts: 1,347 Joined: Dec 2013
RE: How to easily crash an HP Prime
(03-08-2018 08:25 PM)John Colvin Wrote:
(03-08-2018 04:48 AM)Carsen Wrote:  John Colvin. My HP 50g got the right answer of 4.66829167156. I believe the 49G+ should get the right answer as well. Did you accidentally put in the lower and upper bound in the wrong order?

Am I missing something here? How is 4.6668.... the correct answer? If I convert
10 deg. to pi/18 red. in the upper boundary, I get a result of 0.001772.... on my
50G as well. A graph of sin(x^2) clearly indicates that in this interval, the area
under the curve is quite small.

Yes, 10_deg = pi/18_rad, but sin((10_deg)^2) is not the same as sin((pi/18_rad)^2). Plot the sin(x^2) from 0_deg to 10_deg and you'll see it. The integral from 9 to 10 alone is almost 1.

X<> c
-Joe-
03-08-2018, 09:09 PM
Post: #15
 John Colvin Member Posts: 165 Joined: Dec 2013
RE: How to easily crash an HP Prime
(03-08-2018 08:47 PM)Joe Horn Wrote:
(03-08-2018 08:25 PM)John Colvin Wrote:  Am I missing something here? How is 4.6668.... the correct answer? If I convert
10 deg. to pi/18 red. in the upper boundary, I get a result of 0.001772.... on my
50G as well. A graph of sin(x^2) clearly indicates that in this interval, the area
under the curve is quite small.

Yes, 10_deg = pi/18_rad, but sin((10_deg)^2) is not the same as sin((pi/18_rad)^2). Plot the sin(x^2) from 0_deg to 10_deg and you'll see it. The integral from 9 to 10 alone is almost 1.

That''s what I missed, Joe. Thanks.
 « Next Oldest | Next Newest »

User(s) browsing this thread: 1 Guest(s)