Re: HP 49g+ / Probability UTPN Message #2 Posted by hugh steers on 24 July 2006, 2:33 p.m., in response to message #1 by Thomas
let p(x) be the probability from -inf to x. so p(1) = 84.1%, p(2)=97.7% and so on, so you know which way round i'm counting.
i get p(.1129) = .544945, so that's where that number is coming from, its when x is already normalised.
however, 1-p((.1129-11.5)/sqrt(961)) = .643312
so thats where the other number is coming from, first you normalise, then, in this case, you're calulating 1-p(x). sometimes this is called r(x) = 1-p(x) for some calculators.
hope this helps,
|