|Re: I'll try this...|
Message #2 Posted by Vieira, Luiz C. (Brazil) on 6 Jan 2003, 4:40 p.m.,
in response to message #1 by Stephan (Germany)
thanks for the new guidelines.
I was reading again the original article and I saw one thing I did not notice before: polarity.
As a voltage source, any battery is supposed to have a low internal resistence WHEN fully charged and direct current is considered. I always plugged the battery poles as if the battery is a polarized charge for the capacitor circuit, say, serial connection: (-) pole from capacitor in (+) pole in the battery and (+) pole from capacitor in (-) pole in the battery. This way, the current surge flows the same way as if the battery is connected as the voltage source in a circuit. The scheme when power supply and battery are connected with the same polarity is uded only to charge the battery. Am I wrong?
I agree with you when you mention a lower voltage, but I always thouhgt of a high voltage peak (and current) to "remove" the short-circuit cause, an internal, abnormal connection between both (+) and (-) poles. Will it have the same efficiency with lower voltages? As we are not working with "manufacturers recommended operating conditions", I was reasoning about it.
I still have three 1.5 volt cells from an 82143A batt pack that did not have their internal short-circuit removed and I'll give them a try.
Thank you all for the brainy, valualble guidelines.