Creating a tangent circle in graphing.
10-13-2017, 06:12 PM
Post: #1
Creating a tangent circle in graphing.
I am trying to create a tangent circle on my calculator between two lines ( 90 degree angle). So I can see how well my radius will fit thanks.
10-14-2017, 12:31 AM
Post: #2
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
There is an infinite number of solutions to this problem. If you draw a line that bisects the angle between the 2 lines, the center of the circle must lie on this line and it's radius will be the perpendicular distance to each line.....should be the same for both lines. This will give you an infinite number of circles with center along that bisecting line.
10-14-2017, 08:46 AM
Post: #3
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
If you create a 3rd line, you can use the incircle function in the geometry app to create a circle that is a tangent to all 3 lines.....with the 3rd line there is only one solution.
10-14-2017, 10:58 AM
Post: #4
RE: Creating a tangent circle in graphing.
Thanks that works perfect, one last question tho how can I make a line go at a certain angle.
Thanks
10-14-2017, 01:57 PM
Post: #5
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
You could specify 2 points using polar coordinates and convert them to rectangular coordinates and draw the line through the 2 points.
10-16-2017, 06:22 PM
Post: #6
RE: Creating a tangent circle in graphing.
Hmmm could you screenshot on how you did that.
Thanks
10-17-2017, 12:13 AM
Post: #7
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
I didn't. It was just a recommendation....There are operators to convert between polar and rect coordinates. LOok those up and play around with it...
10-17-2017, 12:48 AM
Post: #8
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
Lets say you want a line going through the origin at an angle of pi/2, then you'd enter the polar form, as 1<angle>(pi/2)
<angle> is shift-multiply
pi is shift-3

Then, you can just hit the angle key (shift-multiply) and it'll convert it into a complex number. You can then take the complex number as rectangular coordinates and 0,0 and draw a line between them....

...something like that :-)
10-17-2017, 02:12 AM
Post: #9
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
I was curious how to do it so I tried it....here is how you'd do it.
Use the geometry app.
Create first funciton, GA, to be a point(1<angle>(pi/4))
Create second point, GB, to be point(0,0)
Then, create a line between them, GB, line(GA,GB)
....and there is your line at an angle of pi/4.

BTW, the best place to find stuff is the wiki...
http://www.wiki4hp.com/doku.php?id=prime:start
10-17-2017, 03:49 AM
Post: #10
 webmasterpdx Senior Member Posts: 541 Joined: Sep 2015
RE: Creating a tangent circle in graphing.
I just added a polar/rect page to the wiki that might interest you...
http://www.wiki4hp.com/doku.php?id=prime:polrec
10-18-2017, 01:58 PM
Post: #11
RE: Creating a tangent circle in graphing.
Ok I am kinding understanding that I will keep messing with it more to get familiar with it.
 « Next Oldest | Next Newest »

User(s) browsing this thread: 1 Guest(s)