# Line slope calculator 3x+7y=42

**Straight line given by points A[0; 6] and B[7; 3]**

## Calculation:

**Slope-intercept form of line:**y = -0.4286x+6

**Canonical form of the line equation:**3x+7y-42 = 0

**Parametric form of the line equation:**

x = 7t

y = -3t+6 ; t ∈ R

**Slope:**m = -0.4286

**Slope angle of line: φ =**-23°11'55″ = -0.4049 rad

**X intercept:**x

_{0}= 14

**Y intercept:**y

_{0}= q = 6

**Distance line from the origin:**d

_{0}= 5.5149

**The length of the segment AB: |AB| =**7.6158

**Vector: AB =**(7; -3)

**Normal vector: n =**(3; 7)

**Midpoint of the segment AB: M =**[3.5; 4.5]

**Perpendicular Bisector equation:**7x-3y-11 = 0

**Vector OA = (0; 6) ; |OA| = 6**

**Vector OB = (7; 3) ; |OB| = 7.6158**

**Scalar product OA .OB = 18**

**Angle ∠ AOB = 66°48'5″ = 1.1659 rad**