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[BUG] limit of nthroot(x) != limit x^(1/n)
02-20-2014, 03:00 PM
Post: #1
[BUG] limit of nthroot(x) != limit x^(1/n)
This is probably related to: http://www.hpmuseum.org/cgi-sys/cgiwrap/...ead=255313

If you calculate the limit n->infinity for x^(1/n) the CAS returns 1 (which is the expected answer)
But if you compute the limit n-> infinity of n-th root of x the CAS returns infinitieth-root(x) (this forum needs an equation editor!)
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02-20-2014, 03:07 PM
Post: #2
RE: [BUG] limit of nthroot(x) != limit x^(1/n)
(02-20-2014 03:00 PM)Stefan Wrote:  (this forum needs an equation editor!)

Have you tried using LaTeX syntax? For example:

\[ \lim_{n\to \infty} \sqrt[n]{x} \]

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02-20-2014, 03:22 PM
Post: #3
RE: [BUG] limit of nthroot(x) != limit x^(1/n)
Oh, that's cool. Didn't know that. Thanks! I'll use that in my next bug post which I will write right now ;-)
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