## Question

The point on the parabola *y*^{2} = 8*x* at which the normal is inclined at 60^{0} to the x-axis has the coordinates

### Solution

*y*^{2} = 8*x*

…(2)

Out this in (1), 16 (3) = 8*x*

.

Point *P*(*x, y*)is *P* .

#### SIMILAR QUESTIONS

Equation of locus of a point whose distance from point (*a*, 0) is equal to its distance from y-axis is

Through the vertex *O* of parabola *y*^{2} = 4*x*, chords *OP* and *OQ* are drawn at right angles to one another. The locus of the middle point of *PQ *is

The locus of the mid-point of the line segment joining the focus to a moving point on the parabola *y*^{2} = 4*ax* is another parabola with directrix

The equation of common tangent to the curves *y*^{2} = 8*x* and *xy* = –1 is

From the point (–1, 2) tangent lines are drawn to the parabola *y*^{2} = 4*x*, then the equation of chord of contact is

For the above problem, the area of triangle formed by chord of contact and the tangents is given by

A point moves on the parabola *y*^{2} = 4*ax*. Its distance from the focus is minimum for the following value(s) of *x*.

The line* x – y* + 2 = 0 touches the parabola *y*^{2} = 8*x* at the point

If *t* is the parameter for one end of a focal chord of the parabola *y*^{2} = 4*ax*, then its length is

The length of the latus rectum of the parabola 9*x*^{2} – 6*x* + 36*y* + 19 = 0 is