Graph plot oddity
10-18-2015, 08:43 PM
Post: #1
 lrdheat Senior Member Posts: 574 Joined: Feb 2014
Graph plot oddity
In function app, I have functions in all 10 slots. I'm finding that, when simultaneously plotting functions, F7(X) will not plot if I have F6(X) & F5(X) plot, also F7(X) fails to plot if F4(X) & F5(X) plot. To be clear, F7(X) is not plotting for any case in which the above is a subset of the checked functions to plot
10-18-2015, 08:53 PM
Post: #2
 Tim Wessman Senior Member Posts: 2,238 Joined: Dec 2013
RE: Graph plot oddity
Could you copy/paste your formulas here? Everything seems to plot fine on my quick test.

TW

Although I work for the HP calculator group, the views and opinions I post here are my own.
10-18-2015, 09:04 PM
Post: #3
 lrdheat Senior Member Posts: 574 Joined: Feb 2014
RE: Graph plot oddity
How do I send this from the physical devise on my iPad?

F5 is -(x^2-1)/2 * (x-2) * (x+1)

F6 is -(x^2+1)/2 * (x-2) * (x+1)

F7 is -((x+1)^2)/2 * (x-1) * (x-2)

Hope you feel better soon!
10-18-2015, 09:34 PM
Post: #4
 primer Member Posts: 135 Joined: Sep 2015
RE: Graph plot oddity
(10-18-2015 09:04 PM)lrdheat Wrote:  F5 is -(x^2-1)/2 * (x-2) * (x+1)

F7 is -((x+1)^2)/2 * (x-1) * (x-2)

as F5 is equal to F7, that's normal that asking to display both will only display one.

in CAS, type F5-F7, press Simplif... result is zero because F5 == F7.

primer
10-18-2015, 10:59 PM
Post: #5
 lrdheat Senior Member Posts: 574 Joined: Feb 2014
RE: Graph plot oddity
Thanks!

That is great...I typed in the two functions, and did not recognize them as equivalent!
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