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Statistics issue with NORMALD_CDF?
03-23-2015, 08:19 PM
Post: #1
Statistics issue with NORMALD_CDF?
I'm trying to run normal cumulative distribution functions in "Home" mode.

First, this seems to work fine in CAS:

normald_cdf(10, 0.2, 10.4) ==> 0.9772...

But when I try this in Home mode, I get:

10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF() ==> 1

which is wrong...

However, the test case in help works fine:

0 ENTER 1 ENTER 2 ENTER NORMALD_CDF() ==> 0.9772...

which gives the same as in the CAS test case above because they both correspond to 2 sigma...

So am I doing something wrong in Home mode? Or is the mean value and standard deviation being treated as 0, 1 rather than 10, 0.2?

Thanks

-Jonathan
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03-23-2015, 08:33 PM
Post: #2
RE: Statistics issue with NORMALD_CDF?
(03-23-2015 08:19 PM)Jonathan Cameron Wrote:  I'm trying to run normal cumulative distribution functions in "Home" mode.
First, this seems to work fine in CAS:
normald_cdf(10, 0.2, 10.4) ==> 0.9772...
But when I try this in Home mode, I get:
10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF() ==> 1
which is wrong...
...

hello Jonathan,
also by in Home (with RPN) it' wrong, but it's ok in Algebric mode and TextBook, so I think there is something not correct concerning RPN...

Salvo

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03-23-2015, 08:43 PM
Post: #3
RE: Statistics issue with NORMALD_CDF?
(03-23-2015 08:19 PM)Jonathan Cameron Wrote:  But when I try this in Home mode, I get:

10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF() ==> 1

So am I doing something wrong in Home mode? Or is the mean value and standard deviation being treated as 0, 1 rather than 10, 0.2?

I think you need to tell it how many arguments you take off the stack, so please try

10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF(3)

Cheers, Terje
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03-24-2015, 12:37 AM
Post: #4
RE: Statistics issue with NORMALD_CDF?
(03-23-2015 08:43 PM)Terje Vallestad Wrote:  
(03-23-2015 08:19 PM)Jonathan Cameron Wrote:  But when I try this in Home mode, I get:

10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF() ==> 1

So am I doing something wrong in Home mode? Or is the mean value and standard deviation being treated as 0, 1 rather than 10, 0.2?

I think you need to tell it how many arguments you take off the stack, so please try

10 Enter 0.2 Enter 10.4 Enter NORMALD_CDF(3)

Cheers, Terje

Thanks Terje!

I did not know you had to tell it how many arguments to process. It makes sense that the number of arguments is necessary since 1, 3, and 4 arguments all are legal but mean different things.

-Jonathan
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