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(28/48/50) Lambert W Function
01-30-2024, 04:04 PM
Post: #41
RE: (28/48/50) Lambert W Function
(01-30-2024 02:52 PM)Gil Wrote:  FNL=
«
WHILE x .4 >=
REPEAT 'x/(sqrt(1+x)+1)' ->NUM 'x' STO x FNL 2 * x SQ - 'fnl' STO
END 'x/(x+2)' ->NUM 'X2' STO X2 DUP * 'X4' STO 'X4*(5005-X4*(5082-X4*969))/(15015-X4*(24255-X4*(11025-X4*1225)))' ->NUM 'X4' STO 'X2*(X4+X4-x)' ->NUM 'fnl' STO
»

Again, FNL is a recursive function!
I don't know RPL, but the fact it started with WHILE already look wrong.

Also, FNL is unsuitable for big x. (excess recursions cause unnessary rounding errors)
For big x, return LOGP1(X)-X, or simply LN(1+X)-X, is faster and better.

Again, please read thread: Accurate x - log(1+x)

If your question is only about accurate log(1+x)-x, please posted there.
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01-31-2024, 07:10 PM
Post: #42
RE: (28/48/50) Lambert W Function
John,
Great your LambertW implementation!
Comparing your results with my proper HP50G program, I think that for special cases like:

k=-1 & input x tiny like {x=-1E-496 or x=-1E-497 or x=-1E-497 or x=-1E-499 }

or k=0 and x=1E-499

your program cannot give a correct answer.

Almost a pity.

Regards,
Gil
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