What's the function of a function variable's function?
10-29-2014, 12:24 PM
Post: #1
 DrD Senior Member Posts: 1,132 Joined: Feb 2014
What's the function of a function variable's function?
Interestingly, I found nothing in the user guide regarding this usage of a function variable:

CAS enter:
r(t):=[t-sin(t) 1-cos(t)]

Produces:
r:=(t)->BEGIN [t-sin(t),1-cos(t)]; END;
(t)->BEGIN [t-sin(t),1-cos(t)]; END;

Example:
A revolving cycloid at t=0 (rest), position r(0) => [0,0] rotates to pi radians, r(π) => [π,2], completes a full cycle at r(2*π) => [2*π,0].

Is there any further information on this?

-Dale-
10-29-2014, 02:18 PM (This post was last modified: 10-29-2014 02:19 PM by Han.)
Post: #2 Han Senior Member Posts: 1,878 Joined: Dec 2013
RE: What's the function of a function variable's function?
You can find more info by looking at the documentation for xcas/giac.

There isn't anything special about a variable whose content is a function. It's supposed to reflect a mathematical function. So you can create functions by simply using the form:

function_name(var_name):= <expression in terms of var_name>;

This is typical for any CAS. The CAS also knows how to handle functional algebra. So you can define two functions f(x) and g(t) and ask the CAS to compute h:=f+g, and then use compute, say, h(3).

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10-29-2014, 03:22 PM
Post: #3
 DrD Senior Member Posts: 1,132 Joined: Feb 2014
RE: What's the function of a function variable's function?
The fact that it created the function in much the same way as 'Define' might, was new to me. The 'BEGIN and END' surround wasn't something I expected, but now that I have learned of that behavior, I imagine it will become quite useful.

Thanks for the xcas/giac reference.

-Dale-
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