Laplace transform of pde ∂u/∂t = 0.01 * ∂²u/∂x² using the Prime

09202023, 11:28 AM
(This post was last modified: 09202023 11:29 AM by Anthony The Koala.)
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Laplace transform of pde ∂u/∂t = 0.01 * ∂²u/∂x² using the Prime
Generally if we have a function that is "common" we can find L{f(x}} and get the corresponding transform.
Example L{5} = 5/s. You can find the table in any 2nd year book. I would like to know how to get a Laplace transform on the Prime. For example: pde ∂u/∂t = 0.01 * ∂²u/∂x² Boundary conditions: u(0, t) = 0 u(1, t) = 200 I tried the laplace L{∂u/∂t} expecting to get L{∂u/∂t} = sU(x,s)  u(x,0) BUT IN THE PRIME laplace(∂u/∂t) I get "X Syntax Error" Can you get laplace transforms of derivatives? Thank you Anthony, Sydney 

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