Is it possible to do other kinds of systems of linear equations?

08012023, 05:38 PM
Post: #1




Is it possible to do other kinds of systems of linear equations?
The linear solver only takes x+y=z
x+y=z Is it possible to do an equation like 10x4y=8 8y=kx30 

08022023, 07:38 AM
Post: #2




RE: Is it possible to do other kinds of systems of linear equations?
(08012023 05:38 PM)batx27 Wrote: Is it possible to do an equation like As the User Guide says (Section 16 on page 312 in my copy) equations must be in the form: ax + by = k (for the 2x2 solver) ax + by + cz = k (for the 3x3 solver) Simply rearrange any equations to fit the appropriate form and then enter the coefficients into the boxes. 10x  4y = 8 is already [10]x + [4]y = [8] 8y = kx  30 becomes [k]x + [8]y = [30] (presumably you know "k") 

08022023, 10:06 PM
Post: #3




RE: Is it possible to do other kinds of systems of linear equations?
Hey Mark. I actually don't know the value for K, so I wondering if there was a shortcut or program to find K, but I guess I will keep looking. Thanks tho


08032023, 05:00 AM
Post: #4




RE: Is it possible to do other kinds of systems of linear equations?
Assuming the parameter k>0, you should see something like:
x=14/(k20) and y=(752k)/(k20) Best, Aries ;) 

08032023, 05:51 AM
Post: #5




RE: Is it possible to do other kinds of systems of linear equations?
(08022023 10:06 PM)batx27 Wrote: Hey Mark. I actually don't know the value for K, so I wondering if there was a shortcut or program to find K, but I guess I will keep looking. Thanks tho There is no way to solve a 2 equation system with 3 unknowns. One of them (k in this case) will have to remain unknown and you will have to express the x and y in terms of k. Your system will have infinite solutions, unless you have a restriction for k. For each separate value of k you will have a different solution. 

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