problem with canonical_form

08132018, 07:35 PM
(This post was last modified: 08132018 07:36 PM by compsystems.)
Post: #1




problem with canonical_form
canonical_form(x^26*x+y^2+10*y+18) returns poly1[153+(x3)^2]
Source: free book "Doing Mathematics withScientic WorkPlace" https://www.sciword.co.uk/manuals/ http://www.wolframalpha.com/input/?i=can...10*y%3D18 canonical form x^26*x+y^2+10*y=18 => (x  3)^2 + (y + 5)^2  16 = 0 LO SUFICIENTEMENTE BUENO ES ENEMIGO DE LA EXCELENCIA. 

08142018, 08:44 AM
Post: #2




RE: problem with canonical_form
According to the help provided by the calculator and also by the User Guide, canonical_form works with one variable only. Your function has two: x and y.


08152018, 10:38 AM
Post: #3




RE: problem with canonical_form  
08152018, 01:44 PM
(This post was last modified: 08152018 02:12 PM by Komanguy.)
Post: #4




RE: problem with canonical_form
(08132018 07:35 PM)compsystems Wrote: canonical_form(x^26*x+y^2+10*y+18) returns poly1[153+(x3)^2] You got this weird result because your cas variable ‘y’ is no longer symbolic. You must reset it. Quote:canonical form x^26*x+y^2+10*y=18 => Unless I’m wrong, the canonical form of a quadratic expression ax^2+bx+c is a[(x+b/2a)^2−(b^2−4ac)/4a^2], x is the only variable If you have two variables you should use the canonical_form fonction for each single variable. In this example, instead of canonical_form(x^26*x+y^2+10*y+18) you should use canonical_form(x^26*x)+canonical_form(y^2+10*y+18) It’s more in accordance with the definition of a canonical form. Guy R. KOMAN, hp 50G, hp Prime Rev. C 

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