MANPIP
04-07-2014, 06:00 PM
Post: #1
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
MANPIP
I just recently lost a program titled "MANPIP" when my batteries went dead and I did not get the new ones installed in time. The program was an open channel flow calculator for circular pipe using Manning's equation. The program was loaded into my HP-41CX in the late 1980's via a wand from barcode. I do not have the barcode to re-install it. I had it on magnetic cards, but the first of 5 cards was ruined by the drive wheel (became gooey) of my card reader that no longer works. Therefore, I am reaching out to see if anyone has this program written down or in barcode??? The first screen would show: Qf D S y Qp after XEQ MANPIP. The program would prompt you for "n=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns. Solution would then go through the same (allowing you to also check your input) and also give you V (velocity).

The program I am describing above is not the Pipe Slide Rule, although it is possible the programmer started with it.

If anyone could help me out that would be great.

I am a Civil Engineer and although I can use the computer to solve these problems, my 41CX was portable into the field. I would like to regain that ability.
04-07-2014, 06:53 PM
Post: #2
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-07-2014 06:00 PM)Jerussi Wrote:  If anyone could help me out that would be great.
Is the Gaucklerâ€“Manning formula used?

Then it shouldn't be too difficult to recreate your program. Even providing the bar-code should be easy.
Without knowledge of hydraulics I assume D = 2Rh and y = k. But then what are Qf and Qp?

Kind regards
Thomas
04-07-2014, 07:35 PM
Post: #3
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Qf is full flow in Cubic feet/sec
Qp is partial flow also in CFS

Attached File(s)
04-07-2014, 07:37 PM
Post: #4
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Also, the program was in English units only
04-07-2014, 07:38 PM
Post: #5
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Rh is the hydrauolic radius not the radius of the pipe. D or d is the diameter of the pipe.
04-07-2014, 11:05 PM
Post: #6
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-07-2014 07:35 PM)Jerussi Wrote:  Qf is full flow in Cubic feet/sec
Qp is partial flow also in CFS
How are these related to Q?

That certainly helped a lot!

Quote:The first screen would show: Qf D S y Qp after XEQ MANPIP.
Are they related to the top-row (LBL A-E)?

Quote:The program would prompt you for "n=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns.
As far as I understand all these parameters are needed to calculate Q = Q(n, d, y, S).
Is this what should be calculated?
Or can you specify Q as well and just omit one of the others?

Kind regards
Thomas
04-08-2014, 06:01 PM
Post: #7
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Yes they are shown in that order accross the screen and then the A-E buttons are assigned to them accordingly.

Also yes you can just input what you know of the variables and it solves for the unknowns - You can specify the Diameter (D or d) and the flow Q and solve for slope S. or.. input the slope and flow and solve for diameter. The N factor is always input.
04-08-2014, 06:04 PM
Post: #8
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Qp and Qf are both Q (flow in cubic feet/sec)
Qp is partial flow and is derived from the Manning's equation.
Qf is full flow where the equation changes to Q=VA, where V is velocity in Ft/sec and A is the cross sectional Area of the inside of the pipe in Feet.
04-08-2014, 09:29 PM
Post: #9
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
I left the Q= out of "The program would prompt you for "n=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns." it should have read: The program would prompt you for "n=", "Q=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns.
04-09-2014, 08:05 AM
Post: #10
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-08-2014 09:29 PM)Jerussi Wrote:  I left the Q= out of "The program would prompt you for "n=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns." it should have read: The program would prompt you for "n=", "Q=", "D=", "S=", "y=" and you would enter the knowns and R/S through the unknowns.
That makes more sense. Was it possible to solve for D or y? Because that appears to be a little more difficult.

Quote:Qp and Qf are both Q (flow in cubic feet/sec)
Qp is partial flow and is derived from the Manning's equation.
Would you enter Qp in the program when prompted for "Q="?

Quote:Qf is full flow where the equation changes to Q=VA, where V is velocity in Ft/sec and A is the cross sectional Area of the inside of the pipe in Feet.
Does that mean: $$Qf=V\cdot\frac{\pi D^2}{4}$$?

Could you provide some examples for the calculations?

Though I'm sure this isn't yet what you had here's a first approach:
Code:
LBL "MANNING" "N = ?" PROMPT FS?C 22 STO 00 "D = ?" PROMPT FS?C 22 STO 01 "S = ?" PROMPT FS?C 22 STO 02 "Y = ?" PROMPT FS?C 22 STO 03 1 RCL 03      ; y 2 * RCL 01      ; d / - ACOS 2 * STO 04      ; theta = 2 arccos(1 - 2 y / d) ENTER SIN - RCL 01      ; d X^2 * 8 / STO 05      ; A = (theta - sin(theta)) d^2 / 8 RCL 04      ; theta / RCL 01      ; d / 2 *           ; R = A / P LASTX       ; 2 3 / Y^X         ; R^(2/3) RCL 02      ; S SQRT * RCL 00      ; n / 1.49        ; k * STO 06      ; V = k R^(2/3) S^(1/2) / n RCL 05      ; A * STO 07      ; Q = V A "N = " ARCL 00 PROMPT "D = " ARCL 01 PROMPT "S = " ARCL 02 PROMPT "Y = " ARCL 03 PROMPT "A = " ARCL 05 PROMPT "V = " ARCL 06 PROMPT "Q = " ARCL 07 PROMPT END

You are only asked for n, D, S and y. But you don't have to re-enter them when they aren't different from the last calculation. Only A, V and Q are calculated.

Cheers
Thomas

Attached File(s)
04-09-2014, 02:13 PM
Post: #11
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Wow thanks.
I hand keyed it into a 41CV that I use at my desk since my 41CX is at home today. I still have to find my wand. It is at home somewhere. But thank you for the barcode.
When I tried to run the program I am getting a "DATA ERROR". I then hit PRGM and it stopped on line 23 / (divide).
Question: when I key in FS?C 22 do I include the space between the C and the 22? I tried it both ways and didn't have any luck.
Do I need a space between the letters and the = sign?
There is no need to show the results for "A"
Not important but the order I remember was N, Q, D, S, y, V

I will see if I can get it to work at lunch today.
Again, thank you very much for the effort you have put in.

last question: How do you create the barcode?

I will find some examples of the calculations today.

Regards,
Mark
04-09-2014, 02:28 PM
Post: #12
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
I believe it needs to ask for Q= also. You are correct that if the variable was input it would display in the results and nothing would need to be entered.

For example: I would enter N=0.013, Q=12 (CFS), D= no input, S=.01 (for 1%), Y= no input and it would calculate the size pipe in diameter (inches) required to flow 12 CFS at 1% in a concrete pipe with a N=0.013.

or I could enter N=0.013, Q= no input, D=15 (inches), S=.01, Y= no input and it would calculate the flow "Q" in CFS that a 15 inch concrete pipe can carry at 1%.
04-09-2014, 05:20 PM
Post: #13
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-09-2014 02:13 PM)Jerussi Wrote:  When I tried to run the program I am getting a "DATA ERROR". I then hit PRGM and it stopped on line 23 / (divide).
Code:
22  RCL 01      ; d 23  /
That's because d wasn't specified or was set to 0.

Quote:Question: when I key in FS?C 22 do I include the space between the C and the 22?
[XEQ] [ALPHA] FS?C [ALPHA]
Now it should display:
FS?C __
Then you can enter 22:
FS?C 22

Quote:I tried it both ways and didn't have any luck.
I hope it works now.

Quote:Do I need a space between the letters and the = sign?
No. You can do as you like. It's just how the text is prompted. I can remove these.

Quote:There is no need to show the results for "A"
Not important but the order I remember was N, Q, D, S, y, V
I can change that easily.

Quote:I will see if I can get it to work at lunch today.
Again, thank you very much for the effort you have put in.

last question: How do you create the barcode?
I used: nutstudio. But there are other tools as well. IIRC even online.

Quote:I will find some examples of the calculations today.
That will help.

Cheers
Thomas
04-09-2014, 06:58 PM
Post: #14
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-09-2014 02:28 PM)Jerussi Wrote:  For example: I would enter N=0.013, Q=12 (CFS), D= no input, S=.01 (for 1%), Y= no input and it would calculate the size pipe in diameter (inches) required to flow 12 CFS at 1% in a concrete pipe with a N=0.013.

or I could enter N=0.013, Q= no input, D=15 (inches), S=.01, Y= no input and it would calculate the flow "Q" in CFS that a 15 inch concrete pipe can carry at 1%.
Does it mean that "Y= no input" implies y=d?
In this case the formulas are much simpler:
• $$A=\frac{\pi}{4}d^2$$
• $$P=\pi d$$
• $$R=\frac{d}{4}$$.

Could it be that you specified: N, Q, D, S and then y was calculated?

Cheers
Thomas
04-09-2014, 08:20 PM
Post: #15
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
Yes Y would be calculated and the corresponding V too. In the specific example I gave you to solve for the Q, yes Y is also calculated and in that example y is equal to D as it is solving for full flow.

Now if I would enter N=0.013, Q=12 (CFS), D= 21 (inches), S=.01 (for 1%), Y= no input the program will solve for Y and V. The answers should be something close to Y= 1.14 feet or 13.68 inches and V = 7.26 Ft/sec. In this case Y is not equal to D.

I have attached a storm sewer design spreadsheet we use in our site plans. This should show the formulas in the cells that are computed as examples of the calculations - I hope it helps some. Ignore the elliptical pipe sizes as I am only concerned with circular pipe. This is not as useful as the other attachement described below.

I have also attached a document "080_14320.pdf" with alot of information on the Manning's equation with all the formulas. In this document they call "Y" out as "h". This is a good reference.

Attached File(s)
04-09-2014, 09:50 PM
Post: #16
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
BTW, I did fix the FS?C 22 to the correct input method per your info. I checked it line by line too. I am still getting the "DATA ERROR" but now it is stopping at line 52 /
Also, the program is not prompting me for the input at the begining. I do not understand this as I see all the "PROMPT"s in the program listing???
04-10-2014, 08:56 AM
Post: #17
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-09-2014 09:50 PM)Jerussi Wrote:  BTW, I did fix the FS?C 22 to the correct input method per your info. I checked it line by line too. I am still getting the "DATA ERROR" but now it is stopping at line 52 /
Code:
51   RCL 00      ; n 52   /
That means that n is 0. You can just as well use the following to set that value:
0.013
STO 00

Quote:Also, the program is not prompting me for the input at the begining. I do not understand this as I see all the "PROMPT"s in the program listing???
You say that PROMPT doesn't work properly?

From the manual:
Quote:The PROMPT instruction in a program displays the contents of the ALPHA register and stops program execution.

Thanks for the attachments. It will take a while to read them. Thus you have to be a little patient with me. It turned out the problem is a little more difficult than I assumed at first sight.

Cheers
Thomas
04-10-2014, 12:28 PM
Post: #18
 Jerussi Junior Member Posts: 20 Joined: Apr 2014
RE: MANPIP
OK. I'm not sure what I keyed in incorrectly - but I located my wand last night and was able to get your program to run after loading it from the barcode!

Time is no problem - I really appreciate what you are doing. Also, this event has had me get reacquainted with my 41's.

Just a side bar - I originally had a HP-34C that my Father bought me to go to college (Texas A&M). After two years of Engineering school I basically had to get a 41 to keep up with other students. It was a 41CV. After college I would use the 34C for daily computing tasks at my desk until it was stolen (I would leave it ontop of my desk charging at night). I still have all the books, charger, case, box, etc. for it. So I went full time 41CV. Then one day after I was investigating synthetic programing, I bought and tried to install a Turbo board in the CV. Well that was the last time that calculator worked. Then I bought my CX which I still use. I have also aquired a free CV from a co-worker which I use on a daily basis. I keep the CX for design programs and use the CV to keep the "miles" off of my CX.

Have a good day,
Mark
04-12-2014, 04:29 AM
Post: #19
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
This is the 2nd version of the MANNING program. It uses the top row of the keys similar to how you can solve TVM problems with the HP-12C. I used the following layout but this could be changed:

[N] [Q] [D] [S] [Y]

You can use [STO] + key to enter the known data and [RCL] + key to read it. This works because registers 01-05 are used for these 5 variables.
So you enter the known values and then press the key to calculate the unknown value. After a while the result is displayed. If you press [R/S] the velocity is displayed as well.

If you want to calculate the full flow you have to set both D and Y to the same value. If you know N, Q and S you can only solve for full flow with the key [D]. It's currently not possible to solve for D when N, Q, S and Y are given. I could be wrong but I assumed that isn't used often.

However you can solve for Y when N, Q, D and S are given. For certain values there might be two solutions but only the smaller is calculated. A fixed point iteration is used to solve the equation numerically. Thus the calculation may take a little longer especially for small values of $$\theta$$.

Examples
You have to run this once to initialize the calculator:
[XEQ] "MANNING"

Partial flow:
n = 0.0130 Q = 7.2400 d = 2.7500 S = 0.0020 y = 1.0441

.013 [STO] [N]
7.24 [STO] [Q]
2.75 [STO] [D]
.002 [STO] [S]
[Y]
Y=1.0441
[R/S]
V=3.5000

Full flow: (y = d)
n = 0.0110 Q = 11.9559 d = 2.0000 S = 0.0020 y = 2.0000

.011 [STO] [N]
2 [STO] [D] [STO] [Y]
.002 [STO] [S]
[Q]
Q=11.9559
[R/S]
V=3.8057

Registers
00 k
01 n
02 Q
03 d
04 S
05 y
06 $$\theta$$
07 A
08 V

Code:
LBL "MANNING" RAD SF 27           ; set USER mode .3048           ; 1 ft in m 1/X 3 1/X Y^X STO 00          ; k = 1.485918577 "N Q D S Y" PROMPT ;================================================== LBL A           ; calculate n XEQ 01          ; R^(2/3) RCL 00          ; k * RCL 04          ; S SQRT * XEQ 02          ; V / STO 01          ; n = k * R^(2./3.) * sqrt(S) / V "N=" GTO 03 ;================================================== LBL B           ; calculate Q XEQ 01          ; R^(2/3) RCL 00          ; k * RCL 04          ; S SQRT * RCL 01          ; n / STO 08          ; V = k * R^(2./3.) * sqrt(S) / n RCL 07          ; A * STO 02          ; Q = V * A "Q=" GTO 03 ;================================================== LBL C           ; calculate d RCL 01          ; n RCL 02          ; Q * PI / RCL 00          ; k / RCL 04          ; S SQRT / 3 Y^X 4 5 Y^X             ; 4^5 * 8 1/X Y^X STO 03          ; d = (4^5 * (n * Q / pi / k / sqrt(S))^3)^(1/8) STO 05          ; y = d X^2 PI * 4 / STO 07          ; A = pi * d^2 / 4 XEQ 02          ; V RCL 03 "D=" GTO 03 ;================================================== LBL D           ; calculate S XEQ 01          ; R^(2/3) XEQ 02          ; V RCL 01          ; n * RCL 00          ; k / X<>Y            ; R^(2/3) / X^2 STO 04          ; S = (V * n / k / R^(2/3))^2 "S=" GTO 03 ;================================================== LBL E           ; calculate y RCL 01          ; n RCL 02          ; Q * RCL 00          ; k / RCL 04          ; S SQRT / 3 Y^X 2 13 Y^X * RCL 03 8 Y^X / STO 09          ; L = 2^13 * (n * Q / k / sqrt(S))^3 / d^8 ;...............; calculate initial guess 3 1/X Y^X 6.758860947     ; max q / SQRT 2 * 1 X<>Y - ACOS 5.278107138     ; max theta * PI /               ; max_t*acos(1-2*sqrt(q/max_q))/pi STO 06 ;...............; fixed point iteration LBL 00 RCL 06          ; theta SIN RCL 06          ; theta X^2 RCL 09          ; L * .2 Y^X +               ; theta' = sin(theta)+(L*theta^2)^.2 ENTER X<> 06          ; theta - ABS RND X>0? GTO 00 1 RCL 06          ; theta 2 / COS - RCL 03          ; d * 2 / STO 05          ; y = d * (1 - cos(theta / 2)) / 2 RCL 06          ; theta ENTER SIN - RCL 03          ; d X^2 * 8 / STO 07          ; A = d^2 * (theta - sin(theta)) / 8 XEQ 02          ; V RCL 05 "Y=" GTO 03 ;================================================== LBL 01          ; calculate theta, A and R^(2/3) 1 RCL 05          ; y 2 * RCL 03          ; d / - ACOS 2 * STO 06          ; theta = 2 arccos(1 - 2 y / d) ENTER SIN - RCL 03          ; d X^2 * 8 / STO 07          ; A = (theta - sin(theta)) d^2 / 8 RCL 06          ; theta / RCL 03          ; d / 2 *               ; R = A / P LASTX           ; 2 3 / Y^X             ; R^(2/3) RTN ;================================================== LBL 02          ; calculate V RCL 02          ; Q RCL 07          ; A / STO 08          ; V RTN ;================================================== LBL 03          ; prompt result ARCL X PROMPT "V=" ARCL 08         ; V AVIEW END

Best regards
Thomas

Attached File(s)
04-12-2014, 04:37 AM
Post: #20
 Thomas Klemm Senior Member Posts: 2,100 Joined: Dec 2013
RE: MANPIP
(04-09-2014 08:20 PM)Jerussi Wrote:  Yes Y would be calculated and the corresponding V too. In the specific example I gave you to solve for the Q, yes Y is also calculated and in that example y is equal to D as it is solving for full flow.

Now if I would enter N=0.013, Q=12 (CFS), D= 21 (inches), S=.01 (for 1%), Y= no input the program will solve for Y and V. The answers should be something close to Y= 1.14 feet or 13.68 inches and V = 7.26 Ft/sec. In this case Y is not equal to D.

With the new version of the program you would enter:
.013 [STO] [N]
12 [STO] [Q]
21 [ENTER] 12 / [STO] [D]
.01 [STO] [S]
[Y]
Y=1.1385
[R/S]
V=7.2432

Cheers
Thomas
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