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HP 15C and INT(1/√(1-x),0,1)
11-26-2017, 11:13 PM (This post was last modified: 11-26-2017 11:16 PM by peacecalc.)
Post: #3
RE: HP 15C and INT(1/√(1-x),0,1)
Hello Salvo,

try your little program LBL1 without step 03 and 05 (both ENTER).

Because if you use your function with lets say 0.2 you get:

at step 01: -0.2 x-reg
at step 02: -0.2 x-reg, y-reg
at step 04: 0.8 x-reg, -0.2 yreg
at step 05: 0.8 x-reg, 0.8 yreg, -0.2 z-reg
at step 07: 1/√0.8 x-reg, 0.8 yreg, -0.2 z-reg

but the values in y-reg and z-reg are useless for the build-in integral-program, it may interfer with next looping because then t-reg is loaded and this reg copies it's value to the z-reg if there is a stack-down command.

Okay, Dieter was fast as flash, but I can't delete my post.
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Messages In This Thread
HP 15C and INT(1/√(1-x),0,1) - salvomic - 11-26-2017, 07:51 PM
RE: HP 15C and INT(1/√(1-x),0,1) - peacecalc - 11-26-2017 11:13 PM
RE: HP 15C and INT(1/√(1-x),0,1) - JimP - 01-12-2018, 04:18 AM
RE: HP 15C and INT(1/√(1-x),0,1) - tgray - 01-09-2018, 03:42 PM



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