HP 15C and INT(1/√(1-x),0,1)
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11-26-2017, 11:13 PM
(This post was last modified: 11-26-2017 11:16 PM by peacecalc.)
Post: #3
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RE: HP 15C and INT(1/√(1-x),0,1)
Hello Salvo,
try your little program LBL1 without step 03 and 05 (both ENTER). Because if you use your function with lets say 0.2 you get: at step 01: -0.2 x-reg at step 02: -0.2 x-reg, y-reg at step 04: 0.8 x-reg, -0.2 yreg at step 05: 0.8 x-reg, 0.8 yreg, -0.2 z-reg at step 07: 1/√0.8 x-reg, 0.8 yreg, -0.2 z-reg but the values in y-reg and z-reg are useless for the build-in integral-program, it may interfer with next looping because then t-reg is loaded and this reg copies it's value to the z-reg if there is a stack-down command. Okay, Dieter was fast as flash, but I can't delete my post. |
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